Re: confusion -
Re: confusion -
- Subject: Re: confusion -
- From: Pascal Robert <email@hidden>
- Date: Fri, 18 Mar 2011 21:49:53 -0400
I never had to include all properties from a relation, but to get some of them, I do something like this:
filter.include(InvitationUser.INVITATION.dot(Invitation.YOURPROPERTY1)
filter.include(InvitationUser.INVITATION.dot(Invitation.YOURPROPERTY2)
...
> Can't get ERRest to include attributes along a keypath?
>
> I show the attributes of the "invitation" relationship, but I wanted this filter to include attributes for "invitation.author" - I can only get the type and id for "author"?
>
>
>
>
>
> public WOActionResults inboxAction() {
> EOQualifier qual = InvitationUser.USER.eq(user());
> ERXRestFetchSpecification<InvitationUser> fetchSpec = new ERXRestFetchSpecification<InvitationUser>(InvitationUser.ENTITY_NAME, qual, null, queryFilter(), null, 25);
> ERXKeyFilter filter = ERXKeyFilter.filterWithAll();
> filter.include(InvitationUser.INVITATION).includeAttributesAndToOneRelationships();
> return response(fetchSpec, filter);
> }
>
>
>
>
>
>
> (
> {
> "id" = "1";
> "invitation" = {
> "author" = {
> "type" = "Person";
> "id" = "1";
> };
> "status" = "<com.webobjects.foundation.NSKeyValueCoding$Null>";
> "mtly" = {
> "type" = "Mtly";
> "id" = "27";
> };
> "id" = "1";
> "active" = "true";
> "created" = "2011-01-10 05:00:00 Etc/GMT";
> "type" = "Invitation";
> "name" = "<com.webobjects.foundation.NSKeyValueCoding$Null>";
> "adjusted" = "2011-01-10 05:24:01 Etc/GMT";
> };
> "type" = "InvitationUser";
> "user" = {
> "type" = "Person";
> "id" = "1";
> };
> },
> {
> "id" = "2";
> "invitation" = {
> "author" = {
> "type" = "Person";
> "id" = "1";
> };
> "status" = "<com.webobjects.foundation.NSKeyValueCoding$Null>";
> "mtly" = {
> "type" = "Mtly";
> "id" = "27";
> };
> "id" = "1";
> "active" = "true";
> "created" = "2011-01-10 05:00:00 Etc/GMT";
> "type" = "Invitation";
> "name" = "<com.webobjects.foundation.NSKeyValueCoding$Null>";
> "adjusted" = "2011-01-10 05:24:01 Etc/GMT";
> };
> "type" = "InvitationUser";
> "user" = {
> "type" = "Person";
> "id" = "1";
> };
> }
> )
>
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| References: | |
| | >confusion - (From: Jesse Tayler <email@hidden>) |