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Re: qualifier with NOT
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Re: qualifier with NOT


  • Subject: Re: qualifier with NOT
  • From: Chuck Hill <email@hidden>
  • Date: Mon, 19 Sep 2011 21:35:30 -0700

On 2011-09-19, at 9:28 PM, David Avendasora wrote:

>
> On Sep 20, 2011, at 10:14 AM, Theodore Petrosky wrote:
>
>> I don't know where that was documented.
>
> You must be new here...
>
> ;-)

LOL

But, for once, it IS documented!
http://developer.apple.com/legacy/mac/library/documentation/InternetWeb/Reference/WO542Reference/com/webobjects/eocontrol/EOQualifier.html


> Using Wildcards and the like Operator
>
> When you use the like or caseInsensitiveLike operator in a qualifier expression, you can use the wildcard characters * and ? to perform pattern matching, for example:
>
>  "lastName like 'Jo*'"
>
>
>
> matches Jones, Johnson, Jolsen, Josephs, and so on.
>
> The ? character just matches a single character, for example:
>
>  "lastName like 'Jone?'"
>
>
>
> matches Jones.
>
> The asterisk character ( ) is only interpreted as a wildcard in expressions that use the like or caseInsensitiveLike operator. For example, in the following statement, the character * is treated as a literal value, not as a wildcard:
>
>           quot;lastName = 'Jo*'"
>
>
>

--
Chuck Hill             Senior Consultant / VP Development

Practical WebObjects - for developers who want to increase their overall knowledge of WebObjects or who are trying to solve specific problems.
http://www.global-village.net/products/practical_webobjects







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References: 
 >Re: qualifier with NOT (From: Theodore Petrosky <email@hidden>)
 >Re: qualifier with NOT (From: David Avendasora <email@hidden>)

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