Apple

result.setObjectForKey(someObject.customer(), "customer");

return response(result, ERXKeyFilter.filterWithAllRecursive());

This will returns all attributes and relationships of customer, adjust the filter if required.

Samuel

Le 8 juin 2016 à 16:22, Rodrigo de Sousa <email@hidden> a écrit :
Hello,

I am using the ERRest in my project and I am having a problem. I changed some attributes to a new relationship, but I want to discover if there is a way to not change my old API request.

For example:

Old request:
{
"customer": {
"email": "email@hidden",
"name": "Rodrigo de Sousa",
"phone": "11 1234-5678"
},
"federalDocument":"123123123"
}

Now, I have a new relationship called Sale Detail that have a customer.

New request:
{
"saleDetail": {
"customer": {
"email": "email@hidden",
"name": "Rodrigo de Sousa",
"phone": "11 1234-5678"
},
"federalDocument":"123123123"
}
}

I know that I can use the ERXKeyFilter.filterWithAllRecursive() and add in the map like in the example below. It works well with primitive attributes, but I can use some like this with an Object (in my case, the Customer)? Is possible to continue using the old request and not break my API?

Example:
filter.addMap("saleDetail.federalDocument", "federalDocument");

With this example, I can use the federalDocument in the old way. I tested here and it works.

I can use some like in the example below?

Example:
filter.addMap("saleDetail.customer", "customer");

When I tried to use this, this exception was thrown:

java.lang.IllegalArgumentException: There is no to-one relationship named 'saleDetail.customer' on 'CommercialInvoice'.
at er.rest.ERXRestRequestNode.updateObjectWithFilter(ERXRestRequestNode.java:1296)
at er.rest.ERXRestRequestNode.createObjectWithFilter(ERXRestRequestNode.java:863)
at er.rest.routes.ERXRouteController.create(ERXRouteController.java:670)
at er.rest.routes.ERXRouteController.create(ERXRouteController.java:638)

Thanks for any help!
Rodrigo.
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