Re: Shell script help
Re: Shell script help
- Subject: Re: Shell script help
- From: Xavier Noria <email@hidden>
- Date: Fri, 3 Sep 2004 22:50:46 +0200
On Sep 3, 2004, at 21:15, Eric Ocean wrote:
I'm completely unfamiliar with shell scripting.
How do I invoke this script? (i.e. what parameters)
This script basically tests the output of programs passed in the
command line with known output. Looks like a regression test.
#!/bin/bash
#
TMPOUT=rltest.out
Assigns "rltest.out" to the shell variable TMPOUT.
for prog; do
In each loop a parameter is assigned to the prog variable. That is, if
you call the script like this
$ bash script.sh foo bar baz
then that loop iterates three times, and prog is "foo", "bar", and
"baz", respectively.
for inp in input.*; do
Iterates over the files that match the pattern input.*, as in the
command line. Each corresponding filename is assigned to inp in turn.
echo -n "$prog on $inp ... ";
./$prog < $inp 2>&1 > $TMPOUT;
Executes $prog, which is supposed to be an executable in the current
directory, passing the contents of the file named $inp by stdin, and
redirecting stdout and stderr to $TMPOUT, which is defined to be
"rltest.out".
if diff output.${inp#input.} $TMPOUT > /dev/null; then
echo "ok";
Compares a file whose name shares some pattern with the input file,
except is called output.something, and checks whether there's some
difference with the one created above into $TMPOUT.
If there's no difference, "ok" is echoed to the terminal.
else
echo "FAILED";
rm $TMPOUT
exit 1;
Complains if there was some difference, removes $TMPOUT, and halts with
exit status 1.
fi;
done;
done;
-- fxn
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