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Re: frameworks, dynamic_cast and gcc 4.0
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Re: frameworks, dynamic_cast and gcc 4.0


  • Subject: Re: frameworks, dynamic_cast and gcc 4.0
  • From: Steve Baxter <email@hidden>
  • Date: Tue, 23 Aug 2005 15:55:17 +0100

Hi Andreas,

On 23 Aug 2005, at 14:43, Andreas Grosam wrote:


On 22.08.2005, at 17:56, Steve Baxter wrote:


Hi Stephan,

I ran into a problem like this as well. The problem seems to be a difference in implementation between dynamic_cast in GCC 4.0 and in most other compilers (or at least CodeWarrior and VC++).

It seems that GCC 4.0 treats classes linked in different shared units as different, even if they have the same name. There is some good information here:

http://gcc.gnu.org/faq.html#dso


Yeah, but it is also explained that RTTI symbols *have* to be resolved propperly at load time. That means, if you perform a dynamic_cast in DSO S1 you need to link against the DSO S2, where the class (and all the type info) is defined and you also need to make the RTTI symbols accessible in DSO S2.


Then, only one instance of RTTI is *active*.

It seems that if you load plugins dynamically, RTTI symbols may not be resolved uniquely. I understand that the specification that GCC has adopted assumes that RTTI symbols are resolved, however in the real world they may not be. It should deal properly with this case - I suspect you can define __GXX_MERGED_TYPEINFO_NAMES to 0 to achieve this.


It should be noted that both CW and VC++ compare type_info by name, not by address (for exactly this reason).

You will see this problem if the same source file is linked or included in more than one DSO (dynamic shared object).

Shouldn't i then get link errors (duplicate symbols)??

So then, you are doing something wrong. As mentioned, you need to link against the DSO where the class is defined, instead of including the source module into the calling DSO.

No link error - the DSOs do not link against each other.

More irritatingly, you can run into this problem with fully- inline classes - if the class header is included in more than one DSO, it will end up with two type_info copies, one in each DSO (this can happen very commonly with template code).

These constructs are indeed more complicated, especially dealing with templates. However, if not otherwise stated explicitly in bold face, you can rely on the tools! ;-)

The problem here is, that you don't get linker errors, when you just not link against the DSO where the class template has been instantiated. But you need to.

I'm afraid I don't think the tools work properly - the simple fact is that code that works properly in VC++ and CW does not work in XCode - it compiles and links, but fails at runtime (the worst possible sort of error).


These constructs are said to have "vague linkage":

http://developer.apple.com/documentation/DeveloperTools/gcc-4.0.0/ gcc/Vague-Linkage.html

The reason for the problem seems to be that the GCC writers changed GCC so that type_info was checked for equality by comparing addresses rather than really comparing for equality. Two type_infos with different addresses are always considered to be different even if they are in fact identical. This was done for performance reasons - a pointer comparison is (obviously) faster than a string compare.

That is true. And this works only under the assumption that the symbols (or better objects) have been resolved propperly. Then, there is only one *active* object, and this is the correct one.

As I say, this is not necessarily true in the real world, however much the GCC developers would like it to be true in an academic sense. I would argue that the optimisation they have tried to do is flawed.


I suspect this works OK within a single DSO - the linker discards duplicate copies of the type_info constructs so you end up with only one.

Yes, because the symbols will be resolved at link time, and only one will be made the *active* object.

When you use shared libs, resolving occurs at load time, but the effect is the same: one and only one object will be made the active one.
In case of RTTI, you also need to ensure that the selected active object is the correct one, means, firstly you need to link against the DSO where it is defined, and you also need to export the symbols. Then, and only then, the dynamic linker can resolve the correct symbol at load time.



I am not sure what you are supposed to do in multi-DSO applications where the same template or inline class might be used in several DSOs - I would want then to be treated as identical, but the GCC runtime would not do this. This is probably going to be a show-stopper for us - this works fine in VC++ and CodeWarrior though

Again, ensure you link against the DSO where the class is defined - and do *not* include source modules in more than one DSO which are used in your application.
Unless you only use dynamic_cast to check the type, but also call member functions of this object, you need to link against this DSO anyway!

It is perfectly possible and permissible to call virtual methods of an object without linking to it - all you need is the vtable. A virtual call is, after all, a call by function pointer.


Cheers,

Steve.

Stephen Baxter
Software Development Manager
Improvision
email@hidden
+44-2476-692229


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  • Follow-Ups:
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References: 
 >frameworks, dynamic_cast and gcc 4.0 (From: Stephan Huber <email@hidden>)
 >Re: frameworks, dynamic_cast and gcc 4.0 (From: Steve Baxter <email@hidden>)
 >Re: frameworks, dynamic_cast and gcc 4.0 (From: Andreas Grosam <email@hidden>)

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