Re: Character Array in C
Re: Character Array in C
- Subject: Re: Character Array in C
- From: Michael <email@hidden>
- Date: Mon, 3 Apr 2006 13:32:09 -0700
Thank you all...changing test to type "char" from "void" did the trick.
It fixes this, but I guess leads me to ask this.
If passing a character array is not by value, but by reference, why
does it not work to have test as a "void" type? As, if my
understanding is correct, ( which it probably is not), what is
passed to "test" as an argument is not the "real array" but a pointer
to the first byte of the array "helloworld"
Michael.
On Apr 3, 2006, at 1:08 PM, Ben wrote:
test(helloworld) returns void, and yet you are using it as if it
would evaluate to a char*.
On Mon, 3 Apr 2006, Michael wrote:
Could anyone please offer some advice:
Trying to play with character arrays in C, the code below
generates this error.
Anyone see something wrong?
thank you in advance.
#include <stdio.h>
void test(char s[]);
char helloworld[11];
int main () {
printf("%s", test(helloworld)); // <----Invalid use of void
expression
return 0;
}
void test (char t[])
{
t[0]='H';
t[1]='e';
t[2]='l';
t[3]='l';
t[4]='o';
t[5]=' ';
t[6]='W';
t[7]='o';
t[8]='r';
t[9]='l';
t[10]='d';
t[11]='\0';
}
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