Re: c question
Re: c question
- Subject: Re: c question
- From: William Bumgarner <email@hidden>
- Date: Wed, 29 Mar 2006 19:31:30 -0800
On Mar 29, 2006, at 4:05 PM, Michael wrote:
In my quest to start at the basics, could someone tell me why this
code, in C, will not give the number of characters in the run log. tks
>>>>>>>
#include <stdio.h>
/* counts characters from key board */
int main () {
double i;
for ( i=0; getchar() != EOF; ++i)
;
printf("Number of characters = %.0f\n" , i);
return 0;
}
<<<<<<<<<<<
The code is working correctly, but it will loop in the for() loop
forever until the EOF -- end of file -- is hit. That won't happen
until the input stream is closed. But there isn't a way to close the
input stream.
Well, not quite. The Cocoa text entry system is very emacsen in
nature. As such, certain multi-key sequences work just fine. In
this case, you can hit control-q followed by control-d to close
standard input to the inferior process. control-q means 'input
whatever the heck the user types next as a raw character'. control-d
is a shell shortcut for close stdin. Oddly, you do have to hit
return to have the ctrl-d actually trigger an EOF. No, the return
character is not the EOF, you can hit <ret><ret><ctrl-q><ctrl-d><ret>
and see a count of 2.
And some other random points that seemed to have been confused:
- buffered vs. unbuffered I/O is totally irrelevant. getchar() is
going to get one character at a time, regardless of buffering
semantics. The for() loop is written such that it will only
terminate on EOF.
- whether i is a double or an int is irrelevant, too. Some integer
type would make more sense, but double works, too.
b.bum
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| | >c question (From: Michael <email@hidden>) |