Re: Pointers and arrays
Re: Pointers and arrays
- Subject: Re: Pointers and arrays
- From: Joachim Deelen <email@hidden>
- Date: Tue, 17 Oct 2006 00:06:26 +0200
Hi!
consider the following code:
int main (int argc, const char * argv[]) {
// insert code here...
int i[10];
sub(i);
return 0;
}
void sub(int *aI) {
int i;
for (i = 0; i < 9; i++) {
aI[i] = i;
}
}
I think, you will watch how the array "aI" gets filled within the
function "sub(int *aI)".
Set a breakpoint at "aI[i] = i". Then in the debugger Window, where
the "int *" gets displayed with the address-value of "aI", open the
Context-Menu and select "View Value as...". Change "int *" to "int
[10] *" an press OK (replace [10] with your array size).
Now "aI" gets displayed in a separate Window. Select the small
triangles, to open the tree. After opening the second triangle,
you'll see all the elements of your array!
Hope this Helps
Joachim
Am 15.10.2006 um 13:28 schrieb Michael:
May I ask this.
Using the Standard Tool.
If main() contains integer/char array i[].
If function sub_main() contains a pointer to i, how can I see the
array (not the pointer) in the debugger, other than clicking on
"main", in sub_main(). In other words, I wish to step through the
code in sub_main and watch how the array changes.
Thanks in advance.
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