Re: Viewing A Pointer As An Array
Re: Viewing A Pointer As An Array
- Subject: Re: Viewing A Pointer As An Array
- From: "Sherm Pendley" <email@hidden>
- Date: Thu, 22 May 2008 16:16:42 -0400
Stray '@" in *program*? Did you enter these expressions into the debugger console, or your source code?
sherm--
On Thu, May 22, 2008 at 3:56 PM, Boyd Collier <
email@hidden> wrote:
I'm a little obtuse (okay, more than a little). When I try what you suggested, I get a fatal error message saying "error: stray'@' in program." Could you provide an expanded example?
Boyd
On May 16, 2008, at 11:30 AM, Rick Sustek wrote:
Yes indeed:
create a new _expression_, using the var@len syntax, examples:
For an integer array named foo:
*(int *)foo@256
For a float array named rootBeer:
*(float *)rootBeer@64
This will expand in the expressions window, with a disclosure triangle so you can collapse it, if desired. The length is simply however many you want to display -- even beyond the actual array bounds if you use a number that is larger than the array depth.
Happy, happy, joy, joy,
-Rick
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--
Cocoa programming in Perl:
http://camelbones.sourceforge.net
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