Apple

On Jun 4, 2014, at 13:17 , Ronald Lingl <email@hidden> wrote:

What am I missing here? The condition is if hammers equals 1, which it does. So the statement should always be executed.
That is why he gets the correct result of hammer in the output.

From: Avery Pierce <email@hidden>
To: David Delmonte <email@hidden>
Cc: Xcode Users <email@hidden>
Sent: Wednesday, June 4, 2014 12:08 PM
Subject: Re: Swift question

> If hammers does not equal 1, it also works, but I get a compiler warning: “Will never be executed” on the hammerTitle = " hammer" statement.

Makes sense. If you hard-coded the number of hammers (and there's no place where hammers could possibly change), then there are no code paths that could result in that if block being executed.

On Wed, Jun 4, 2014 at 1:31 PM, David Delmonte <email@hidden> wrote:

Thanks for the fast responses.

I am almost there..

If I do this (thanks Carl):

var hammerTitle = " hammers"

if hammers == 1 {
hammerTitle = " hammer"
}
let toolSummary = "I have \(nails) nails and \(hammers)" + hammerTitle

println("toolSummary: \(toolSummary)")

println()

I do get the desired result if hammers does equal 1. If hammers does not equal 1, it also works, but I get a compiler warning: “Will never be executed” on the hammerTitle = " hammer" statement. It’s the same if I redeclare hammerTitle in the if statement..

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References:

>Re: Swift question (From: Carl Leiby <email@hidden>)

>Re: Swift question (From: David Delmonte <email@hidden>)

>Re: Swift question (From: Avery Pierce <email@hidden>)

>Re: Swift question (From: Ronald Lingl <email@hidden>)

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