Re: Filling variables in the debugger
Re: Filling variables in the debugger
- Subject: Re: Filling variables in the debugger
- From: Jim Ingham <email@hidden>
- Date: Fri, 4 Nov 2005 09:32:39 -0800
On Nov 4, 2005, at 5:45 AM, Karan, Cem (Civ, ARL/CISD) wrote:
I'm trying to figure out when and where one of my arrays gets hosed.
The easiest way for me to do this is to fill the array with a known
pattern, and then see who stomps on the pattern. Ideally, I would be
able to open up the array in the debugger, select all of the variable
positions, and copy one value into every position (kind of like how
you
might do it in a spreadsheet program). Is there a way of doing
this, or
am I being dense? Note that I would like to avoid modifying my code,
and copying into each position one at a time is also really annoying.
In the console, you can do something like:
(gdb) set $i = 0
(gdb) while $i < <ARRAY_SIZE>
set array[$i] = 0xdeadbeef
set $i += 1
end
Dunno if there is an easy cut & paste way to do this in the Variables
View, if not please file a bug, that sounds like a useful enhancement.
Also, how do I get XCode to treat a pointer as an array of something?
For example, I have a void pointer, and a size variable being passed
into a function. Because of the size variable, I know how big the
array
is going to be; I'd like to cast the expression to an array type of a
particular size so that it updates continuously as I step thru my
code.
Is there an easy way of doing this?
The debugger has a kind of funny cast expression for turning a
pointer into an array of a given size. Look at the "artificial
arrays" section in the gdb manual:
file:///Developer/ADC Reference Library/documentation/
DeveloperTools/gdb/gdb/gdb_9.html#SEC58
for the full skinny. To use this, if you have an pointer "foo" which
you know points to an array whose length is given by a variable
"len", open the Expressions window, and enter the expression:
*foo@len
and that will be rendered as an array of length len that you can turn
down and watch in the expressions window.
Hope that helps,
Jim
Thanks,
Cem Karan
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