Re: last day of the month of a date
Re: last day of the month of a date
- Subject: Re: last day of the month of a date
- From: "Nigel Garvey" <email@hidden>
- Date: Thu, 15 Dec 2005 11:29:49 +0000
Bernard Bernu wrote on Thu, 15 Dec 2005 00:58:06 +0100:
>I'd like to get the last day of the month of a date, say current date.
>The only "simple" way I found to get it is : (here adate is a valid
>date)
>
> copy adate to newdate
> set day of newdate to 1
> set newdate to newdate + 31 * days
> set day of newdate to 1
> set newdate to newdate - 1 * days
You can also set the day to 32 to overflow into the following month. The
day of the resulting date is the number of days overflowed:
copy adate to newdate
set day of newdate to 32
set newdate to newdate - (day of newdate) * days
Or:
copy adate to newdate
set newdate's day to 32 - ((adate + (32 - (adate's day)) * days)'s day)
Or, just to keep Gary amused: ;-)
tell (adate + (32 - (adate's day)) * days) to set newdate to it - (its
day) * days
NG
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