Re: last day of the month of a date
Re: last day of the month of a date
- Subject: Re: last day of the month of a date
- From: Bernard Bernu <email@hidden>
- Date: Thu, 15 Dec 2005 12:37:00 +0100
Le 15 déc. 05, à 12:29, Nigel Garvey a écrit :
Bernard Bernu wrote on Thu, 15 Dec 2005 00:58:06 +0100:
I'd like to get the last day of the month of a date, say current date.
The only "simple" way I found to get it is : (here adate is a valid
date)
copy adate to newdate
set day of newdate to 1
set newdate to newdate + 31 * days
set day of newdate to 1
set newdate to newdate - 1 * days
You can also set the day to 32 to overflow into the following month.
The
day of the resulting date is the number of days overflowed:
copy adate to newdate
set day of newdate to 32
set newdate to newdate - (day of newdate) * days
Thanks for this clever trick.
Bernard
Or:
copy adate to newdate
set newdate's day to 32 - ((adate + (32 - (adate's day)) * days)'s
day)
Or, just to keep Gary amused: ;-)
tell (adate + (32 - (adate's day)) * days) to set newdate to it -
(its
day) * days
NG
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Bernard
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