Re: A puzzle
Re: A puzzle
- Subject: Re: A puzzle
- From: Luther Fuller <email@hidden>
- Date: Fri, 21 Nov 2008 15:19:53 -0600
The problem might be clearer if it were restated. Something like
this ...
Given a positive integer, n, and a digit, d > 0, how many times
is the digit d printed in a print-out of all positive integers < 10^n ?
And the answer is ... n * (10 ^ (n - 1)).
But, what if we let d = 0? If we use the brute force script, we find
that if n = 6, then there are 488890 zeros in the print-out. Of
course, the answer is different in this case since leading zeros
aren't printed.
So, what's the pattern and what is the one line formula that yields
the correct instant answer?
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| References: | |
| | >A puzzle (From: Michelle Steiner <email@hidden>) |