Re: A puzzle
Re: A puzzle
- Subject: Re: A puzzle
- From: Skeeve <email@hidden>
- Date: Fri, 21 Nov 2008 23:37:35 +0100
Mark J. Reed schrieb:
So the general result is n * 10^(n-1) - [sum from 1 to n of 10^n] +1.
Or better
n * 10^(n-1) - (10^n - 1) / 9 + 1
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References: | |
| >A puzzle (From: Michelle Steiner <email@hidden>) |
| >Re: A puzzle (From: Luther Fuller <email@hidden>) |
| >Re: A puzzle (From: "Mark J. Reed" <email@hidden>) |