Apple

Thanks Michelle. This worked too.

-----Original Message-----
From: applescript-users-bounces+script2=email@hidden [mailto:applescript-users-bounces+script2=email@hidden] On Behalf Of Michelle Steiner
Sent: Tuesday, September 09, 2008 9:54 AM
To: Applescript Users
Subject: Re: another short form

On Sep 9, 2008, at 6:33 AM, Script2 wrote:

I have string of about 70 characters, I want to check if characters 6,9,12,16,19,24 so on is = “-

I assume that "19" is a typo and you meant to type "18".

If character 6 of aname = “-“ (this gets too lengthy.)

If character 9 of aname = “-“

Try this for starters:

set a to "ab-cd-efghi-ab-cd-efghi-ab-cd-efghi-ab-cd-efghi-ab-cd-efghi-ab-cd-efghi-90"

repeat with i from 3 to count of a by 3

if character i of a is "-" then

display dialog "character " & i & " is -"

else

display dialog "character " & i & " is not -"

end if

end repeat

You will need to add some error checking to test for an overrun at the end of the string.

-- Michelle

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References:
	>RE: another short form (From: "Script2" <email@hidden>)