Re: Correcting AGE_INFO
Re: Correcting AGE_INFO
- Subject: Re: Correcting AGE_INFO
- From: Bert Groeneveld <email@hidden>
- Date: Thu, 4 Feb 2010 11:21:24 +0100
Hello Mark, thanks for your answer.
Would you be so kind to put that into a real code block for me?
Bert.
On 4 feb 2010 (5), at 11:08, Mark J. Reed wrote:
Well, you could start by doing age_info - 2* age_info div 7.
Then just count backwards (age_info mod 7) days from now and subtract
any weekends in there.
On Thursday, February 4, 2010, Bert Groeneveld
<email@hidden> wrote:
set D to current datetell application "Finder" set M to
modification date of alias myFile -- myFile was of course set to
some file earlier in the scriptend tellset AGE_INFO to round (D -
M) / days rounding up -- is always an integerset AGE_INFO to
correct_AGE_INFO(AGE_INFO, D, M)
on correct_AGE_INFO(AGE_INFO, D, M) -- what to put here? (as less
code as possible, of course)end correct_AGE_INFO
Hello,I'm breaking my head about finding some "super algorythm" for
this:I want to correct AGE_INFO, by omitting the days of the
weekend (saturday and sunday)Three possible examples (among many
others):If the weekday of D is thursday and the weekday of M is
friday and AGE_INFO is 7, then I want to correct AGE_INFO by -2
(one weekend in between)If the weekday of D is tuesday and the
weekday of M is friday and AGE_INFO is 12, then I want to correct
AGE_INFO by -4 (2 weekends)If the weekday of D is wednesday and the
weekday of M is monday and AGE_INFO is 3, then I want to do nothing.
Thanks in advance for any help,
Bert.
--
Mark J. Reed <email@hidden>
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