Re: Detect if third word in string contains a number

Subject: Re: Detect if third word in string contains a number
From: theDaniel <email@hidden>
Date: Fri, 11 May 2012 19:23:17 -0400

I don't quite understand everything, but there seems to be a bug somewhere.

If I put one non-number word on the clipboard (ex. "he", "winds"), then condition 2 is called (?)

I modified your code slightly to give me some feedback:

get the clipboard as text --

set _selection to result

-- Identify which word's the number.

set numberWordNumber to 1

repeat with thisWord in _selection's words

if (thisWord is in "363534332313029282726252422120191817161514110") then exit repeat

set numberWordNumber to numberWordNumber + 1

end repeat

-- Act accordingly.

if (numberWordNumber is 1) then

-- The first word's the number.

say "word one is the number" using "Bruce"

else if (numberWordNumber is 2) then

-- The second word's the number.

say "word two is the number" using "Victoria"

else if (numberWordNumber is 3) then

-- The third word's the number.

say "word three is the number" using "Alex"

set word1 to word 1 of _selection

if (word1 is in "I II III") then set the clipboard to ((count word1) as text) & space & text from word 2 to -1 of _selection

else -- (numberWordNumber > 3).

error say "None of the first three words of the selection is a number."

end if

-Daniel

On May 10, 2012, at 10:20AM, Nigel Garvey wrote:

-- Identify which word's the number.
set numberWordNumber to 1
repeat with thisWord in _selection's words
   if (thisWord is in "363534332313029282726252422120191817161514110") then exit repeat
   set numberWordNumber to numberWordNumber + 1
end repeat
-- Act accordingly.
if (numberWordNumber is 1) then
   -- The first word's the number.
else if (numberWordNumber is 2) then
   -- The second word's the number.
else if (numberWordNumber is 3) then
   -- The third word's the number.
   set word1 to word 1 of _selection
   if (word1 is in "I II III") then set the clipboard to ((count word1) as text) & space & text from word 2 to -1 of _selection
else -- (numberWordNumber > 3).
   error "None of the first three words of the selection is a number."
end if

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References:
	>Re: Detect if third word in string contains a number (From: Nigel Garvey <email@hidden>)
	>Re: Detect if third word in string contains a number (From: Nigel Garvey <email@hidden>)

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