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Re: Detect if third word in string contains a number

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Re: Detect if third word in string contains a number

Subject: Re: Detect if third word in string contains a number
From: Thomas Fischer <email@hidden>
Date: Sun, 13 May 2012 12:13:51 +0200

Hi Daniel,

there is a logical error in your script.

The loop

repeat with thisWord in _selection's words

…

will run until a number is encountered, else it will run through all the words.

Thus the case of failure is

numberWordNumber = count of (_selection's words) +1

Thus your evaluation should start with

if (numberWordNumber > (count (_selection's words))) then

say "There is no number in the selection."

else if (numberWordNumber is 1) then

…

Best

Thomas

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References:
	>Re: Detect if third word in string contains a number (From: Nigel Garvey <email@hidden>)
	>Re: Detect if third word in string contains a number (From: Nigel Garvey <email@hidden>)
	>Re: Detect if third word in string contains a number (From: theDaniel <email@hidden>)

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