Apple

Le 22/02/2014 à 20:46, David Crowe <email@hidden> a écrit :

Steve;

Thanks for showing that alternative.

I think the problem is that I'm relying on AppleScript to convert the letter for the arithmetic comparison. The following code works properly:

set c to "E"
considering case
set cnum to (ASCII number c)
if (ASCII number "a") ≤ cnum and cnum ≤ (ASCII number "z") then
display dialog "Character '" & c & "' is lower case."
else if (ASCII number "A") ≤ cnum and cnum ≤ (ASCII number "Z") then
display dialog "Character '" & c & "' is upper case."
end if
end considering

More cumbersome, but more explicit.

- David Crowe

On Feb 22, 2014, at 12:21 PM, Steve Thompson <email@hidden> wrote:

Erm, don’t know. This does work

set c to "E" as text
considering case
if c is not in "abcdefghijklmnopqrstuvwxyz" then
display dialog "Character '" & c & "' is upper case."
end if
end considering

so I’m assuming it has something to do with the way AppleScript evaluates the inequalities when they involve text. Could possibly be a bug unless someone else knows different.

Steve

On 22 Feb 2014, at 18:15, David Crowe <email@hidden> wrote:

Why does this not work? It prints out that "E" is lower case.

set c to "E"
considering case
if "a" ≤ c and c ≤ "z" then
display dialog "Character '" & c & "' is lower case."
end if
end considering

I've tried this on Mavericks and 10.6 and get the same thing. Using "Smile" and the standard AppleScript editor gives the same result.

What am I missing?

- David Crowe

References:
	>Re: Considering case... (From: Steve Thompson <email@hidden>)