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Re: Enumerator and
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Re: Enumerator and


  • Subject: Re: Enumerator and
  • From: Ondra Cada <email@hidden>
  • Date: Tue, 9 Apr 2002 18:03:53 +0200

On Tuesday, April 9, 2002, at 05:40 , Onar Vikingstad wrote:

I'm trying to do something that's seeminly easy:

It's even considerably easier than you presumed ;)

to "convert" an array (records) into a special formatted string (I chose to use enumerator and while function to have full control). But I keep getting run errors when this action (doit) is executed:

- (IBAction)doit:(id)sender
{
NSEnumerator* enumerator = [records objectEnumerator];
NSMutableString *tempString = [NSMutableString stringWithCapacity:4];
id tempObject,index;

while ( (index = [enumerator nextObject]) ) {
tempObject = [records objectAtIndex:[index intValue]];
[tempString appendString:[[records objectAtIndex:[index intValue]] componentsJoinedByString:@":"]];
}

...since enumerator returns array objects, not indices. You wanted

id o;
while (o=[en nextObject])
[tempString appendString:[o description]];

or something like that. I regret to say that I can't make sense of the part

appendString:[... componentsJoinedByString:@":"]

which would make sense only if your array (records) contained nested arrays, whilst it seems to contain some dictionaries (since "[NSCFDictionary intValue]: selector not recognized").
---
Ondra Cada
OCSoftware: email@hidden http://www.ocs.cz
2K Development: email@hidden http://www.2kdevelopment.cz
private email@hidden http://www.ocs.cz/oc
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  • Follow-Ups:
    • Re: Enumerator and
      • From: Andy Lee <email@hidden>
References: 
 >Enumerator and (From: Onar Vikingstad <email@hidden>)

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