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Re: Enumerator and
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Re: Enumerator and


  • Subject: Re: Enumerator and
  • From: Andy Lee <email@hidden>
  • Date: Tue, 9 Apr 2002 12:11:59 -0400

At 5:40 PM +0200 4/9/02, Onar Vikingstad wrote:
I'm trying to do something that's seeminly easy: to "convert" an array (records) into a special formatted string (I chose to use enumerator and while function to have full control). But I keep getting run errors when this action (doit) is executed:

[NSCFDictionary intValue]: selector not recognized
[NSCFDictionary intValue]: selector not recognized

Here's my little snippet of code:

- (IBAction)doit:(id)sender
{
NSEnumerator* enumerator = [records objectEnumerator];
NSMutableString *tempString = [NSMutableString stringWithCapacity:4];
id tempObject,index;

while ( (index = [enumerator nextObject]) ) {
tempObject = [records objectAtIndex:[index intValue]];
[tempString appendString:[[records objectAtIndex:[index intValue]] componentsJoinedByString:@":"]];
}

NSLog(@"Array: %@", [tempString self]);
}

You're misunderstanding what "[enumerator nextObject]" returns. It returns an actual element from your array -- the first element the first time you call it, the second element the second time you call it, etc. So your code can actually be simpler:

NSEnumerator* enumerator = [records objectEnumerator];
NSMutableString *tempString = [NSMutableString stringWithCapacity:4];
id tempObject;

while ( (tempObject = [enumerator nextObject]) ) {
[tempString appendString:[tempObject componentsJoinedByString:@":"]];
}

NSLog(@"Array: %@", tempString);

(While I was at it I simplified the final NSLog statement as well -- you can just say "tempString" instead of "[tempString self]".)

--Andy
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  • Follow-Ups:
    • Re: Enumerator and
      • From: Onar Vikingstad <email@hidden>
References: 
 >Enumerator and (From: Onar Vikingstad <email@hidden>)

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