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Re: passing pointers
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Re: passing pointers


  • Subject: Re: passing pointers
  • From: Angela Brett <email@hidden>
  • Date: Mon, 30 Dec 2002 23:23:22 +1300

David is right about returning a pointer, you probably only need to return obj since obj is most likely a pointer to an object anyway. You'd only need to return *obj if obj is a pointer to a pointer to an object. I guess you don't want to return &obj since that would be an object ** and your method is declared as returning an object *.

Anyway, here's my contribution: you are not calling the right function. -function: as you have implemented it takes an argument, but you are calling a method -function which does not take any arguments. You should call it like this:

obj2=[outlet function:self];

but since function: does not do anything with the argument, you could get rid of it altogether, and change it to:

declaration:
- (object *) function;
implementation:
-(object *) function
{
return obj;
}
call:
obj2 = [outlet function];
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References: 
 >Re: passing pointers (From: David Rio Vierra <email@hidden>)

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