Re: passing pointers
Re: passing pointers
- Subject: Re: passing pointers
- From: Aaron Boothello <email@hidden>
- Date: Mon, 30 Dec 2002 06:17:55 -0500
the objects are both declared as pointers.
the first one (obj1 is allocated the memory and initialized.
the second one is NOT allocated any memory, but instead im implementing
the declaration and implementation as you have outlined below.
when i call the method/function(im not sure what to call it at this
point), i do the following...
obj2 = [outlet getObject:self]
so now, obj2 should be pointing to the same object, correct.
alright, now for another question....
lets say i have two separate front ends(views) for each of these
objects.... and both views accept input that change the object..... so,
the information displayed on both vies should be the same at all times
regardless of where the information is being altered. correct ?
Thanks.
On Monday, December 30, 2002, at 05:23 AM, Angela Brett wrote:
David is right about returning a pointer, you probably only need to
return obj since obj is most likely a pointer to an object anyway.
You'd only need to return *obj if obj is a pointer to a pointer to an
object. I guess you don't want to return &obj since that would be an
object ** and your method is declared as returning an object *.
Anyway, here's my contribution: you are not calling the right
function. -function: as you have implemented it takes an argument, but
you are calling a method -function which does not take any arguments.
You should call it like this:
obj2=[outlet function:self];
but since function: does not do anything with the argument, you could
get rid of it altogether, and change it to:
declaration:
- (object *) function;
implementation:
-(object *) function
{
return obj;
}
call:
obj2 = [outlet function];
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