Re: atoi()
Re: atoi()
- Subject: Re: atoi()
- From: "Dr. H. Nikolaus Schaller" <email@hidden>
- Date: Sun, 19 Jan 2003 12:38:51 +0100
You are welcome!
One thing I forgot is handling of negative numbers:
>
int atoi(char *str) { int n=0; if(*str=='-') return -atoi(str+1);
>
while(*str >='0' && *str <='9') n=10*n+(*str++-'0'); return n; }
Nikolaus
Am Sonntag, 19.01.03 um 01:38 Uhr schrieb Philip George:
>
Now that's an answer I can sink my teeth into. Without the smoke and
>
mirrors, it's easy to see that atoi() will always work, whether the
>
API is pulled or not. Great idea.
>
>
Thank you.
>
>
- Philip
>
>
quoted from digest ----------
>
>
Hi,
>
good idea to solve this discussion thread. To me it seems to need less
>
typing effort to submit a one-liner (cited from memory from old K&R
>
Standard C) than a discussion about libraries, standards, OS versions
>
etc.:
>
>
int atoi(char *str) { int n=0; while(*str >='0' && *str <='9')
>
n=10*n+(*str++-'0'); return n; }
>
>
This will work as long as the machine code can somehow be
>
interpreted...
>
>
Or try: sscanf(str, "%d", &i) instead of i=atoi(str)
>
>
HNS
>
>
>
-------------------------
>
>
+-------------------+
! email@hidden !
+-------------------+
_______________________________________________
cocoa-dev mailing list | email@hidden
Help/Unsubscribe/Archives:
http://www.lists.apple.com/mailman/listinfo/cocoa-dev
Do not post admin requests to the list. They will be ignored.
| References: | |
| | >atoi() (From: Philip George <email@hidden>) |