atoi()
atoi()
- Subject: atoi()
- From: Philip George <email@hidden>
- Date: Sat, 18 Jan 2003 18:38:41 -0600
Now that's an answer I can sink my teeth into. Without the smoke and
mirrors, it's easy to see that atoi() will always work, whether the API
is pulled or not. Great idea.
Thank you.
- Philip
quoted from digest ----------
Hi,
good idea to solve this discussion thread. To me it seems to need less
typing effort to submit a one-liner (cited from memory from old K&R
Standard C) than a discussion about libraries, standards, OS versions
etc.:
int atoi(char *str) { int n=0; while(*str >='0' && *str <='9')
n=10*n+(*str++-'0'); return n; }
This will work as long as the machine code can somehow be interpreted...
Or try: sscanf(str, "%d", &i) instead of i=atoi(str)
HNS
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