Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
- Subject: Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
- From: Steve Bird <email@hidden>
- Date: Thu, 17 Jun 2004 14:32:13 -0400
On Jun 17, 2004, at 2:12 PM, Graham J Lee wrote:
On 2004-06-17 18:07:10 +0100 Steve Bird <email@hidden> wrote:
On Jun 17, 2004, at 11:38 AM, Uwe Jagoda wrote:
hello folks,
maybe this is trivial - but not for me. From time to time i ask
myself:
What's behind the curtain ?
sin(4*pi^2*t) 0 >= t <= pi/3
AS WRITTEN, it's nonsensical.
OK, pointless bit of offtopicness, but 0>=t<=pi/3 is perfectly valid.
It means the same as t<=0 though. For instance, t=-1 satisfies both
conditions.
Maybe you can explain the sense of using "0>=t<=pi/3" when no number
that meets the first condition will NOT meet the second.
Maybe you can explain the sense of specifying an infinite range for a
(assumed computer program) function.
I'm still betting on the typo...
----------------------------------------------------------------
Steve Bird
Culverson Software - Elegant software that is a pleasure to use.
www.Culverson.com (toll free) 1-877-676-8175
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