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Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
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Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?


  • Subject: Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
  • From: Graham J Lee <email@hidden>
  • Date: Thu, 17 Jun 2004 19:45:30 +0100
  • Organization: University of Oxford Department of Redundancy Department

On 2004-06-17 19:32:13 +0100 Steve Bird <email@hidden> wrote:


On Jun 17, 2004, at 2:12 PM, Graham J Lee wrote:

On 2004-06-17 18:07:10 +0100 Steve Bird <email@hidden> wrote:

sin(4*pi^2*t) 0 >= t <= pi/3
AS WRITTEN, it's nonsensical.
OK, pointless bit of offtopicness, but 0>=t<=pi/3 is perfectly valid. It means the same as t<=0 though. For instance, t=-1 satisfies both conditions.

Maybe you can explain the sense of using "0>=t<=pi/3" when no number that meets the first condition will NOT meet the second.

Not everything that is valid makes sense. Look at all the valid Perl code out there ;-)
There are cases when the above condition will arise implicitly, for instance if the range of valid t is computed not entered.

Maybe you can explain the sense of specifying an infinite range for a (assumed computer program) function.


I assumed it was a test message, based on the 'can you read this?' subject.[*] Still, taking your assumption as valid for the sake of response, there are plenty of instances in which an infinite range is required/desired/used in computer programs. A trivial example:

while(1)
{
runThrough++;
/*do funky stuff*/
if(quitCondition) break;
}

there may be an example which requires $\sin(4\pi^2t)$ to be calculated over and over, I can't think of it in any context outside Maple-like languages but I expect that other programmers have come across different challenges to me.

I'm still betting on the typo...


It probably was a typographical mistake. Still, pointless offtopicness ensued :-).

Cheers,

Graham.

[*]I originally thought it was a spam, as did spamassassin :-/
--
Graham Lee
Wadham College
OX1 3PN
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  • Follow-Ups:
    • Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ?
      • From: Kyle Moffett <email@hidden>
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 >Re: sin(4*pi^2*t) 0 >= t <= pi/3, can you read this ? (From: Steve Bird <email@hidden>)

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