Re: NSBezierPath geometry question...
Re: NSBezierPath geometry question...
- Subject: Re: NSBezierPath geometry question...
- From: David Phillip Oster <email@hidden>
- Date: Mon, 11 Apr 2005 09:46:18 -0700
At 7:38 AM -0700 4/11/05, Robert Clair <email@hidden> wrote:
There is no cubic Bezier that is exactly a circular arc, the best you
can do is an approximation. However this isn't what you want - it's a
very bad approximation of an arc.
I've read this claim before but never understood it. Since a
NSBezierPath is a cubic polynomial, why in the world would it have
any trouble representing an arc, which is a quadratic polynomial?:
just set the coefficients of the x^3 term to zero, and it IS a
quadratic polynomial. (or in bezier speak: if the two off axis
control points are in the same place, you've got a quadratic spline,
which should be the same as a segment of arc.
David Phillip Oster
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