• Open Menu Close Menu
  • Apple
  • Shopping Bag
  • Apple
  • Mac
  • iPad
  • iPhone
  • Watch
  • TV
  • Music
  • Support
  • Search apple.com
  • Shopping Bag

Lists

Open Menu Close Menu
  • Terms and Conditions
  • Lists hosted on this site
  • Email the Postmaster
  • Tips for posting to public mailing lists
Re: Tracking rectangles and bezier paths
[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

Re: Tracking rectangles and bezier paths


  • Subject: Re: Tracking rectangles and bezier paths
  • From: Wagner Truppel <email@hidden>
  • Date: Sat, 9 Sep 2006 17:51:53 -0700

Ok, then I have two other suggestions...

a) Upon checking the documentation for NSBezierPath <http:// developer.apple.com/documentation/Cocoa/Reference/ApplicationKit/ Classes/NSBezierPath_Class/NSBezierPath_Class.pdf>, I learned of the method -containsPoint:, which "Returns a Boolean value indicating whether the receiver contains the specified point". Maybe that's all you need, that is, check whether the path contains the mouse point and, if so, redraw the path with a thicker stroke and/or a different color, so as to highlight the path. The documentation is actually not very clear as to whether it's testing for a point being *on* the path or only inside the path's region, so you'll have to try and see.

b) If that's not enough, you can use NSBezierPath's -bounds method to retrieve the bounding rectangle of the path itself (which is never larger than the convex hull of the path's control points, and often smaller) and use that as a fast first-pass on deciding whether or not the mouse is near the path. If the mouse is inside the path's bounds rectangle, then you can retrieve the path's control points and do some math of your own to find out if the mouse point is on the path itself, as follows.

Reading the documentation <http://developer.apple.com/documentation/ Cocoa/Conceptual/CocoaDrawingGuide/CocoaDrawingGuide.pdf>, I learned that NSBezierPath creates *cubic* Bezier curves, that is, curves whose points satisfy the parametric equation

P(t) = (1-t)^3 P0 + 3t(1-t)^2 P1 + 3(1-t)t^2 P2 + t^3 P3

where t is a real number in the closed interval [0,1] and P0, P1, P2, and P3 are the control points (P0 and P3 are the starting and ending points of the curve, whereas P1 and P2 are true control points in the sense that they're not on the curve itself). Wikipedia has an excellent intro to Bezier curves, by the way, if you want to learn more <http://en.wikipedia.org/wiki/Bézier_curve>.

So, once you know that the mouse point is near the path (namely, inside its bounding rectangle), you can retrieve the control points, set P(t) to the mouse point, and solve for t. If you find a solution in the range [0,1], then the mouse point is *on* the path.

Now, solving for t is a little tricky, because it involves solving a polynomial equation of 3rd order (for which a general solution exists but is cumbersome). Moreover, since the P's are two-dimensional entities (points), you need to solve the cubic using only the points' x coordinates (or only their y coordinates), then use the value of t found (if you find one in the interval [0,1], that is) to test whether the parametric equation above is satisfied for the other component. That's more efficient than solving for t twice (once for the x coordinates and once for the y coordinates) and then comparing the two solutions for equality.

To actually solve for t, expand the powers in P(t) above and collect terms of identical powers in t to arrive at something like this

A t^3 + B t^2 + C t + D = 0

where A, B, C, and D are expressions depending on the various control points and on the mouse point, but not on t, and then use the method outlined in, for example, <http://www.karlscalculus.org/pdf/ cubicQuartic.pdf#search="solving cubic polynomials"> to solve for t (using either the x or the y components, as I pointed out above).

Hope this helps.
Wagner

============

The difference between an auto mechanic and a quantum mechanic is that the quantum mechanic can get the car inside the garage without opening the door.


Yes, that is correct. I am interested in highlighting the curve when the mouse is on it. Apple does this very nicely in Space Designer (part of Logic Pro). I would be interested to know how they do this. Anyone from Apple care to comment?

Dave

On Sep 9, 2006, at 11:10 AM, Raphael Sebbe wrote:

Hi,

From what Dave told, I believe he is interested in highlighting the
curve when the mouse is *on* it, as opposed to *inside* the area
defined by it. The convex hull may be too large for tracking purpose.

Raphael

On 9/9/06, Wagner Truppel <email@hidden> wrote:
It's not as hard a math problem as suggested, even if the curve is
not monotonic. Recall that the entire bezier path is contained within
the convex hull of the path's control points so a very simple
solution is to retrieve the control points, compute their convex hull
(which is a convex polygon, in 2 dimensions), and use that as your
tracking area. Computing convex hulls in 2 dimensions is almost
trivial - any decent book on algorithms will tell you how.


Wagner
_______________________________________________
Do not post admin requests to the list. They will be ignored.
Cocoa-dev mailing list      (email@hidden)
Help/Unsubscribe/Update your Subscription:
This email sent to email@hidden


References: 
 >Re: Re: Tracking rectangles and bezier paths (From: Wagner Truppel <email@hidden>)
 >Re: Re: Re: Tracking rectangles and bezier paths (From: "Raphael Sebbe" <email@hidden>)

  • Prev by Date: Re: _NSStateMarker
  • Next by Date: Re: NSTableView using Square Button for image
  • Previous by thread: Re: Re: Re: Tracking rectangles and bezier paths
  • Next by thread: Re: Re: Re: Re: Tracking rectangles and bezier paths
  • Index(es):
    • Date
    • Thread