Re: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
Re: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
- Subject: Re: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
- From: mmalc crawford <email@hidden>
- Date: Wed, 08 Oct 2008 09:55:30 -0700
On Oct 8, 2008, at 9:41 AM, Lee, Frederick wrote:
So all my iVars are accessed via:
@property(nonatomic, retain) iVar; // array, dictionary, etc. <--
collections & objects.
Also, I'm not subclassing these properties.
I've seen examples of releasing the iVars & setting their pointers to
nil.
So I figure, using the self.iVar = nil;
No, that is not Apple-sanctioned best-practice.
So you say:
1) use the [iVar release] directly; yet
2) use the "self.iVar = nil" approach for 'synthesized instance
variables.'
Yes, for synthesized *instance variables*.
So if I understand correctly, what you're saying is that in my
particular circumstance (nonatomic),
'nonatomic' has nothing to do with it.
(and I'm synthesizing collections, strings & objects)
the preferred way is setting the 'self.iVar' to nil; per your example
below.
Correct?
No. I stated specifically "synthesized *instance variables*" and gave
an example:
@interface MyClass : NSObject
{} // **** Note: no instance variables
@property (retain) NSString *aString;
@end
@implementation MyClass
@synthesize aString;
-(void)dealloc {
self.aString = nil; // [aString release]; won't work
}
@end
If instead you had an explicit instance variable:
@interface MyClass : NSObject {
NSString *aString;
}
@property (retain) NSString *aString;
@end
then you would use:
@implementation MyClass
@synthesize aString;
-(void)dealloc {
[aString release];
}
@end
mmalc
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