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RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
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RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?


  • Subject: RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?
  • From: "Lee, Frederick" <email@hidden>
  • Date: Wed, 8 Oct 2008 12:58:07 -0400
  • Thread-topic: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ?

Thank you.
I'm understand.
Shall remedy.
Ric.

-----Original Message-----
From: mmalc crawford [mailto:email@hidden]
Sent: Wednesday, October 08, 2008 11:56 AM
To: Lee, Frederick
Cc: email@hidden
Subject: Re: In dealloc(): ref @property, Can I use "<property object> =
nil; " vs "[<property object> release]; " ?


On Oct 8, 2008, at 9:41 AM, Lee, Frederick wrote:

> So all my iVars are accessed via:
> @property(nonatomic, retain) iVar; // array, dictionary, etc. <--
> collections & objects.
> Also, I'm not subclassing these properties.
> I've seen examples of releasing the iVars & setting their pointers to
> nil.
> So I figure, using the self.iVar = nil;
>
No, that is not Apple-sanctioned best-practice.

> So you say:
> 1) use the [iVar release] directly; yet
> 2) use the "self.iVar = nil" approach for 'synthesized instance
> variables.'
>
Yes, for synthesized *instance variables*.

> So if I understand correctly, what you're saying is that in my
> particular circumstance (nonatomic),
>
'nonatomic' has nothing to do with it.

> (and I'm synthesizing collections, strings & objects)
> the preferred way is setting the 'self.iVar' to nil; per your example
> below.
> Correct?
>
No.  I stated specifically "synthesized *instance variables*" and gave
an example:

     @interface MyClass : NSObject
     {} // **** Note: no instance variables
     @property (retain) NSString *aString;
     @end

     @implementation MyClass
     @synthesize aString;
     -(void)dealloc {
           self.aString = nil;  // [aString release]; won't work
     }
     @end

If instead you had an explicit instance variable:

     @interface MyClass : NSObject {
          NSString *aString;
     }
     @property (retain) NSString *aString;
     @end

then you would use:

     @implementation MyClass
     @synthesize aString;
     -(void)dealloc {
         [aString release];
     }
     @end


mmalc


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References: 
 >In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ? (From: "Lee, Frederick" <email@hidden>)
 >Re: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ? (From: mmalc crawford <email@hidden>)
 >RE: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ? (From: "Lee, Frederick" <email@hidden>)
 >Re: In dealloc(): ref @property, Can I use "<property object> = nil; " vs "[<property object> release]; " ? (From: mmalc crawford <email@hidden>)

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