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Re: How to convert String.Index to UInt?
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Re: How to convert String.Index to UInt?


  • Subject: Re: How to convert String.Index to UInt?
  • From: Roland King <email@hidden>
  • Date: Sat, 16 Aug 2014 17:04:07 +0800

You can’t.

		let s : NSString = "hallo\there"
		let aas = NSMutableAttributedString( string: s, attributes: nil )

		let rangeOfTab  = s.rangeOfString( "\t" )
		if rangeOfTab.location != NSNotFound
		{
			let colour = UIColor.grayColor()
			let aRange = NSRange(location:0, length:rangeOfTab.location )
			aas.addAttribute( NSForegroundColorAttributeName, value: colour, range: aRange )
		}	}

After 1+ months are you sure Swift is worth all this effort?


> On 16 Aug 2014, at 4:30 pm, Gerriet M. Denkmann <email@hidden> wrote:
>
> import Cocoa
>
> let s = "hallo\there"
> let aas = NSMutableAttributedString( string: s, attributes: nil )
>
> let rangeOfTab = s.rangeOfString( "\t" )
> if rangeOfTab != nil
> {
> 	let colour = NSColor.grayColor()
> 	let locationOfTab = rangeOfTab!.startIndex
> 	let aRange = NSRange( location: 0, length: locationOfTab ) <--  error: 'String.Index' is not convertible to 'Int'
> 	aas.addAttribute( NSForegroundColorAttributeName, value: colour, range: aRange )
> }
>
> How can I convert a String.Index into an UInt (or Int or whatever)?
>
> Gerriet.
>
>
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 >How to convert String.Index to UInt? (From: "Gerriet M. Denkmann" <email@hidden>)

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