Re: How to convert String.Index to UInt?
Re: How to convert String.Index to UInt?
- Subject: Re: How to convert String.Index to UInt?
- From: Roland King <email@hidden>
- Date: Sat, 16 Aug 2014 17:04:07 +0800
You can’t.
let s : NSString = "hallo\there"
let aas = NSMutableAttributedString( string: s, attributes: nil )
let rangeOfTab = s.rangeOfString( "\t" )
if rangeOfTab.location != NSNotFound
{
let colour = UIColor.grayColor()
let aRange = NSRange(location:0, length:rangeOfTab.location )
aas.addAttribute( NSForegroundColorAttributeName, value: colour, range: aRange )
} }
After 1+ months are you sure Swift is worth all this effort?
> On 16 Aug 2014, at 4:30 pm, Gerriet M. Denkmann <email@hidden> wrote:
>
> import Cocoa
>
> let s = "hallo\there"
> let aas = NSMutableAttributedString( string: s, attributes: nil )
>
> let rangeOfTab = s.rangeOfString( "\t" )
> if rangeOfTab != nil
> {
> let colour = NSColor.grayColor()
> let locationOfTab = rangeOfTab!.startIndex
> let aRange = NSRange( location: 0, length: locationOfTab ) <-- error: 'String.Index' is not convertible to 'Int'
> aas.addAttribute( NSForegroundColorAttributeName, value: colour, range: aRange )
> }
>
> How can I convert a String.Index into an UInt (or Int or whatever)?
>
> Gerriet.
>
>
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