Re: How to convert String.Index to UInt?
Re: How to convert String.Index to UInt?
- Subject: Re: How to convert String.Index to UInt?
- From: "Gerriet M. Denkmann" <email@hidden>
- Date: Sat, 16 Aug 2014 17:00:31 +0700
On 16 Aug 2014, at 16:04, Roland King <email@hidden> wrote:
> You can’t.
>
> let s : NSString = "hallo\there"
> let aas = NSMutableAttributedString( string: s, attributes: nil )
>
> let rangeOfTab = s.rangeOfString( "\t" )
> if rangeOfTab.location != NSNotFound
> {
> let colour = UIColor.grayColor()
> let aRange = NSRange(location:0, length:rangeOfTab.location )
> aas.addAttribute( NSForegroundColorAttributeName, value: colour, range: aRange )
> } }
>
Thanks. Works fine.
> After 1+ months are you sure Swift is worth all this effort?
Well...
First: I think Swift is going to be the future, so I might as well start learning it now.
But:
The speed of Swift is still not so swift.
I just ran an app which has two versions: the running time in Swift beta 5 is only 76 % of beta 4 (which is a nice improvement), but it is still 10 % slower than Obj-C.
The error messages are not always as helpful as they could be.
The documentation (the two Swift books) is not really complete, nor up to date.
I just looked for "distance" and found only something about km and miles.
And "lazy" is still spelled "@lazy".
Xcode offers about "distance" only MKRoute (whatever that is).
Can only get better.
But I kind of like the language. Feels fresh and new. Going back to ObjC feels like switching from Retina to some old display.
Kind regards,
Gerriet.
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