Re: How to convert String.Index to UInt?
Re: How to convert String.Index to UInt?
- Subject: Re: How to convert String.Index to UInt?
- From: "Gerriet M. Denkmann" <email@hidden>
- Date: Sat, 16 Aug 2014 16:43:01 +0700
On 16 Aug 2014, at 16:25, Stephen J. Butler <email@hidden> wrote:
> Try:
>
> import Cocoa
>
> let s = "hallo\there"
> let aas = NSMutableAttributedString(string: s, attributes: nil)
>
> if let rangeOfTab = s.rangeOfString( "\t" ) {
> let colour = NSColor.grayColor()
> let length = distance(s.startIndex, rangeOfTab.startIndex)
> let aRange = NSRange(location: 0, length: length)
> aas.addAttribute(NSForegroundColorAttributeName, value: colour, range: aRange)
> }
I did try and it works perfectly.
Thanks a lot!
>
> Maybe read more:
>
> http://oleb.net/blog/2014/07/swift-strings/
Very useful text. Thanks for the link!
> On Sat, Aug 16, 2014 at 3:30 AM, Gerriet M. Denkmann <email@hidden> wrote:
> import Cocoa
>
> let s = "hallo\there"
> let aas = NSMutableAttributedString( string: s, attributes: nil )
>
> let rangeOfTab = s.rangeOfString( "\t" )
> if rangeOfTab != nil
> {
> let colour = NSColor.grayColor()
> let locationOfTab = rangeOfTab!.startIndex
> let aRange = NSRange( location: 0, length: locationOfTab ) <-- error: 'String.Index' is not convertible to 'Int'
> aas.addAttribute( NSForegroundColorAttributeName, value: colour, range: aRange )
> }
>
> How can I convert a String.Index into an UInt (or Int or whatever)?
Kind regards,
Gerriet.
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