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Re: MPNotifyQueue takes 500,000 nsec (worst case)
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Re: MPNotifyQueue takes 500,000 nsec (worst case)


  • Subject: Re: MPNotifyQueue takes 500,000 nsec (worst case)
  • From: Kurt Revis <email@hidden>
  • Date: Tue, 22 Oct 2002 13:08:48 -0700

Thanks for the very informative message! Always happy to learn more...

On Tuesday, October 22, 2002, at 11:09 AM, kelly jacklin wrote:

I suggest you use the pthreads APIs directly (<http://www.opengroup.org/onlinepubs/007908799/xsh/pthread.h.html>). They are relatively easy to use, closer to the metal (the MP API is implemented atop pthreads APIs), and the pthread_cond_signal call does not block. Although to be used properly, it must be used in conjunction with a mutex lock, which can contend with the thread on the "other side" of the condition, it is possible through a combination of timed waits (effectively polite polling) to avoid taking that lock, and still ensure proper operation.

How does pthread_cond_signal() manage not to block? It looks like it calls semaphore_signal_thread() (in Mach) which is a kernel call--and I thought all syscalls could possibly block the calling thread.

Do I have an over-simplified view of what's really happening? (Probably!)

Compared to what I'm doing (having the consumer thread sleep for a consistent amount of time when it runs out of data to process), it looks like the approach you're suggesting would allow a smaller amount of buffering between the ioproc and consumer, since the consumer will be woken earlier by the pthread_cond_signal() than it otherwise would have. I'll give it a try.

--
Kurt Revis
email@hidden
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  • Follow-Ups:
    • Re: MPNotifyQueue takes 500,000 nsec (worst case)
      • From: Brian Willoughby <email@hidden>
References: 
 >Re: MPNotifyQueue takes 500,000 nsec (worst case) (From: kelly jacklin <email@hidden>)

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