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Re: ERXSortOrderings ?
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Re: ERXSortOrderings ?


  • Subject: Re: ERXSortOrderings ?
  • From: Mike Schrag <email@hidden>
  • Date: Tue, 14 Dec 2010 12:09:22 -0500

.asc() IS a sort ordering, you can't pass it to sortorderingwithkey  because it's not a key it's a sort ordering.

just get rid of ERXSortOrdering.sortOrderingWithKey entirely and use key.asc().then(whatever).

ms

On Dec 14, 2010, at 12:02 PM, Theodore Petrosky wrote:

> Why does this work:
>
> ERXSortOrderings newOrdering = ERXSortOrdering.sortOrderingWithKey("parentCompany.parentCompanyName", ERXSortOrdering.CompareAscending).then(Client.CLIENT_NAME.asc());
>
> but this doesn't:
>
> ERXSortOrderings newOrdering1 = ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
>
> Here is the error: The method sortOrderingWithKey(String, NSSelector) in the type ERXSortOrdering is not applicable for the arguments (ERXSortOrdering.ERXSortOrderings)
>
> ERXSortOrderings newOrdering2 = ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
>
> ERXSortOrderings newOrdering2 = ERXSortOrdering.sortOrderingWithKey(ParentCompany.PARENT_COMPANY_NAME.asc().then(Client.CLIENT_NAME.asc());
>
> As long as I start out with "string, selector" then I can chain - then, then, etc.
>
> I must have some deep seated misunderstanding of ERXSortOrderings and how to create it.
>
> this one works beautifully: (except on closer examination, I don't understand why it works with the parenthesis around the first element)
>
> ERXSortOrderings newOrdering = ERXSortOrdering.sortOrderingWithKey("version.job.primaryKey", ERXSortOrdering.CompareAscending)
> 		.then(Invoice.VERSION.dot(Version.ITEM_INDEX).asc())
> 		.then(Invoice.VERSION.dot(Version.SUB_VERSION_NUMBER).asc())
> 		.then(Invoice.VERSION.dot(Version.REVISION_NUMBER).asc())
> 		.then(Invoice.INVOICE_DATE.asc() );
>
>
> Ted
>
>
>
>
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References: 
 >ERXSortOrderings ? (From: Theodore Petrosky <email@hidden>)

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