Re: ERXSortOrderings ?
Re: ERXSortOrderings ?
- Subject: Re: ERXSortOrderings ?
- From: Theodore Petrosky <email@hidden>
- Date: Tue, 14 Dec 2010 09:33:43 -0800 (PST)
One last item,
ERXSortOrderings is an mutablearray of EOSortOrderings, but the array cannot have one item.
ERXSortOrderings theCompanyOrder = ParentCompany.PARENT_COMPANY_NAME.asc();
is not good. however,
ERXSortOrdering theCompanyOrder = ParentCompany.PARENT_COMPANY_NAME.asc();
NSArray<EOSortOrdering> companySort = new NSArray<EOSortOrdering>(theCompanyOrder);
parentCompanyDG.setSortOrderings(companySort);
is good.
obviously parentCompanyDG is an ERXDisplayGroup.
Is there a reason that I can not create an ERXSortOrderings with only one item?
Ted
--- On Tue, 12/14/10, Mike Schrag <email@hidden> wrote:
> From: Mike Schrag <email@hidden>
> Subject: Re: ERXSortOrderings ?
> To: "Theodore Petrosky" <email@hidden>
> Cc: email@hidden
> Date: Tuesday, December 14, 2010, 12:09 PM
> .asc() IS a sort ordering, you can't
> pass it to sortorderingwithkey because it's not a key
> it's a sort ordering.
>
> just get rid of ERXSortOrdering.sortOrderingWithKey
> entirely and use key.asc().then(whatever).
>
> ms
>
> On Dec 14, 2010, at 12:02 PM, Theodore Petrosky wrote:
>
> > Why does this work:
> >
> > ERXSortOrderings newOrdering =
> ERXSortOrdering.sortOrderingWithKey("parentCompany.parentCompanyName",
> ERXSortOrdering.CompareAscending).then(Client.CLIENT_NAME.asc());
> >
> > but this doesn't:
> >
> > ERXSortOrderings newOrdering1 =
> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
> >
> > Here is the error: The method
> sortOrderingWithKey(String, NSSelector) in the type
> ERXSortOrdering is not applicable for the arguments
> (ERXSortOrdering.ERXSortOrderings)
> >
> > ERXSortOrderings newOrdering2 =
> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
> >
> > ERXSortOrderings newOrdering2 =
> ERXSortOrdering.sortOrderingWithKey(ParentCompany.PARENT_COMPANY_NAME.asc().then(Client.CLIENT_NAME.asc());
> >
> > As long as I start out with "string, selector" then I
> can chain - then, then, etc.
> >
> > I must have some deep seated misunderstanding of
> ERXSortOrderings and how to create it.
> >
> > this one works beautifully: (except on closer
> examination, I don't understand why it works with the
> parenthesis around the first element)
> >
> > ERXSortOrderings newOrdering =
> ERXSortOrdering.sortOrderingWithKey("version.job.primaryKey",
> ERXSortOrdering.CompareAscending)
> >
> .then(Invoice.VERSION.dot(Version.ITEM_INDEX).asc())
> >
> .then(Invoice.VERSION.dot(Version.SUB_VERSION_NUMBER).asc())
> >
> .then(Invoice.VERSION.dot(Version.REVISION_NUMBER).asc())
> >
> .then(Invoice.INVOICE_DATE.asc() );
> >
> >
> > Ted
> >
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