Re: ERXSortOrderings ?
Re: ERXSortOrderings ?
- Subject: Re: ERXSortOrderings ?
- From: Mike Schrag <email@hidden>
- Date: Tue, 14 Dec 2010 12:53:29 -0500
.asc() = singular form, .ascs() = plural form, so
ERXSortOrdering = one of them, singular
ERXSortOrderings = plural, array subclass
ERXSortOrdering sortOrdering = Person.NAME.asc()
ERXSortOrderings sortOrderingS = Person.NAME.ascs()
you can also do:
ERXSortOrderings sortOrderingS = Person.NAME().asc().array()
ms
On Dec 14, 2010, at 12:33 PM, Theodore Petrosky wrote:
> One last item,
>
>
> ERXSortOrderings is an mutablearray of EOSortOrderings, but the array cannot have one item.
>
> ERXSortOrderings theCompanyOrder = ParentCompany.PARENT_COMPANY_NAME.asc();
> is not good. however,
>
> ERXSortOrdering theCompanyOrder = ParentCompany.PARENT_COMPANY_NAME.asc();
> NSArray<EOSortOrdering> companySort = new NSArray<EOSortOrdering>(theCompanyOrder);
> parentCompanyDG.setSortOrderings(companySort);
> is good.
>
> obviously parentCompanyDG is an ERXDisplayGroup.
>
>
> Is there a reason that I can not create an ERXSortOrderings with only one item?
>
> Ted
>
>
>
> --- On Tue, 12/14/10, Mike Schrag <email@hidden> wrote:
>
>> From: Mike Schrag <email@hidden>
>> Subject: Re: ERXSortOrderings ?
>> To: "Theodore Petrosky" <email@hidden>
>> Cc: email@hidden
>> Date: Tuesday, December 14, 2010, 12:09 PM
>> .asc() IS a sort ordering, you can't
>> pass it to sortorderingwithkey because it's not a key
>> it's a sort ordering.
>>
>> just get rid of ERXSortOrdering.sortOrderingWithKey
>> entirely and use key.asc().then(whatever).
>>
>> ms
>>
>> On Dec 14, 2010, at 12:02 PM, Theodore Petrosky wrote:
>>
>>> Why does this work:
>>>
>>> ERXSortOrderings newOrdering =
>> ERXSortOrdering.sortOrderingWithKey("parentCompany.parentCompanyName",
>> ERXSortOrdering.CompareAscending).then(Client.CLIENT_NAME.asc());
>>>
>>> but this doesn't:
>>>
>>> ERXSortOrderings newOrdering1 =
>> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
>>>
>>> Here is the error: The method
>> sortOrderingWithKey(String, NSSelector) in the type
>> ERXSortOrdering is not applicable for the arguments
>> (ERXSortOrdering.ERXSortOrderings)
>>>
>>> ERXSortOrderings newOrdering2 =
>> ERXSortOrdering.sortOrderingWithKey(Client.PARENT_COMPANY.dot(ParentCompany.PARENT_COMPANY_NAME).asc()).then(Client.CLIENT_NAME.asc());
>>>
>>> ERXSortOrderings newOrdering2 =
>> ERXSortOrdering.sortOrderingWithKey(ParentCompany.PARENT_COMPANY_NAME.asc().then(Client.CLIENT_NAME.asc());
>>>
>>> As long as I start out with "string, selector" then I
>> can chain - then, then, etc.
>>>
>>> I must have some deep seated misunderstanding of
>> ERXSortOrderings and how to create it.
>>>
>>> this one works beautifully: (except on closer
>> examination, I don't understand why it works with the
>> parenthesis around the first element)
>>>
>>> ERXSortOrderings newOrdering =
>> ERXSortOrdering.sortOrderingWithKey("version.job.primaryKey",
>> ERXSortOrdering.CompareAscending)
>>>
>> .then(Invoice.VERSION.dot(Version.ITEM_INDEX).asc())
>>>
>> .then(Invoice.VERSION.dot(Version.SUB_VERSION_NUMBER).asc())
>>>
>> .then(Invoice.VERSION.dot(Version.REVISION_NUMBER).asc())
>>>
>> .then(Invoice.INVOICE_DATE.asc() );
>>>
>>>
>>> Ted
>>>
>
>
>
>
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