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newbie question AjaxSubmitButton and JQuery function
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newbie question AjaxSubmitButton and JQuery function


  • Subject: newbie question AjaxSubmitButton and JQuery function
  • From: Mai Nguyen <email@hidden>
  • Date: Thu, 12 Apr 2012 17:50:56 -0700

Hello List,

I wish to call a JQuery function to show or hide a DIV containing a busy indicator in an AjaxSubmitButton, but calling JQuery directly with the function show() or hide() does not seem to work.
I am a newbie with JQuery, so I would really appreciate if someone can point me in the right direction.

Many thanks,

-mai

Assuming using jquery 1.3.2

<script src=""http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js">http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js" type="text/_javascript_"></script>

here is the description:
<!-- DIV description -->
#myBusy {
 
position:absolute;
alignment-adjust: auto;
display:none; // would this work for JQuery?
 
}

.activityIndicator {
description of the busy indicator
}

 <webobject name = "TestSubmitButton"/> <div id ='myBusy' class="activityIndicator"> 


TestSubmitButton: AjaxSubmitButton {
action = testAction;
value = "test";
onClick = "$('#myBusy').show();";
onComplete = "$('#myBusy').hide();";
updateContainerID = "SearchResultsDiv";

 

}
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