Re: newbie question AjaxSubmitButton and JQuery function
Re: newbie question AjaxSubmitButton and JQuery function
- Subject: Re: newbie question AjaxSubmitButton and JQuery function
- From: David LeBer <email@hidden>
- Date: Thu, 12 Apr 2012 21:00:58 -0400
The Ajax framework already has AjaxBusyIndicator.
Have you tried using it?
D
--
David LeBer
Codeferous Software
On 2012-04-12, at 8:50 PM, Mai Nguyen wrote:
> Hello List,
>
> I wish to call a JQuery function to show or hide a DIV containing a busy indicator in an AjaxSubmitButton, but calling JQuery directly with the function show() or hide() does not seem to work.
> I am a newbie with JQuery, so I would really appreciate if someone can point me in the right direction.
>
> Many thanks,
>
> -mai
>
> Assuming using jquery 1.3.2
>
> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js"; type="text/javascript"></script>
>
> here is the description:
> <!-- DIV description -->
> #myBusy {
>
> position:absolute;
> alignment-adjust: auto;
> display:none; // would this work for JQuery?
>
> }
>
> .activityIndicator {
> description of the busy indicator
> }
>
> <webobject name = "TestSubmitButton"/> <div id ='myBusy' class="activityIndicator">
>
>
> TestSubmitButton: AjaxSubmitButton {
> action = testAction;
> value = "test";
> onClick = "$('#myBusy').show();";
> onComplete = "$('#myBusy').hide();";
> updateContainerID = "SearchResultsDiv";
>
> }
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