Re: For loop shenanigans
Re: For loop shenanigans
- Subject: Re: For loop shenanigans
- From: Jose Commins <email@hidden>
- Date: Sat, 6 Dec 2003 00:06:25 +0000
On 5 Dec 2003, at 21:51, Richard Clark wrote:
Run this code:
#include <stdio.h>
int main (int argc, const char * argv[]) {
int i;
for (i = 0; i < 9; i += 3) {
if (i > 0) printf(", ");
printf("%d", i);
}
return 0;
}
and note that it prints "0, 3, 6" as it should. You'll need to look
elsewhere in your code for the problem (and note that a compiler bug is
a bug of last resort; in 20 years of programming I've found only one
honest compiler bug and that was an odd cross-TOC calling bug when
Apple's PowerPC systems were still in Alpha testing and they were
extensively modifying the compiler.)
...Richard
I have found several (reported) compiler bugs throughout the years -
this is a strange one. I do test first and foremost if it is my code
which is causing the problem. Your code (and the original) works after
I changed some settings as I was so frustrated by the end of it I
reinitialised the whole project. I am finding out exactly what
settings were causing the problem.
I found even tracing through the debugger that 'i' was starting at 3.
If I do a new project in Xcode it works fine. Grr!
On Dec 5, 2003, at 12:41 AM, Matt Gough wrote:
>>> for(i = 0; i < 9; i += 3);
>>> {
>>> ... blah...
>>> }
>>>
>>> i is equal to 3 on entry to the loop, which it shouldn't be.
>>>
>>> Bug in Xcode, or GCC?
>>
>> Short between seat and keyboard? Note semicolon after the 'for'
>> statement
>
Oopsie :o) Thanks for spotting the typo.
> Ignoring the fact that the code is probably not as intended, surely i
> should
> be 9 by the time it gets to ...blah... instead of 3.
It's just an example to show the intended error - the actual code had
a few more bits to it.
Regards,
Jose.
--
Death, taxes and Microsoft. If you put it that way, the first two
don't seem so bad.
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