Re: architecture of bundle launcher app
Re: architecture of bundle launcher app
- Subject: Re: architecture of bundle launcher app
- From: Paul Archibald <email@hidden>
- Date: Fri, 1 Jun 2007 20:59:18 -0700
Not silly at all.
I just stuck it on a thumb drive and took it to the intelMac, which
agrees that it is a PPC app (both the bundled app and its little
executable inside).
When I build on the intelMac, it makes the little guy a UBin, and the
bundle is a UBin too. (I suspect that the Finder is looking at the
executable in the Contents->MacOS folder to decide if the bundle is
PowerPC Intel or UBin).
On Jun 1, 2007, at 5:50 PM, Marcus S. Zarra wrote:
Maybe a silly question, but what does the app show up as when you
display it on an intel machine? Does it still claim to be a PPC app?
Marcus S. Zarra
Zarra Studios LLC
Simply Elegant Software for OS X
www.zarrastudios.com
On Jun 1, 2007, at 6:36 PM, Paul Archibald wrote:
Hey,
I am building a Java app with Xcode. My boss kind of freaked out
when he saw that it was judged to be a PowerPC app and NOT a
Universal Binary (by ArchDetect), and wanted me to "fix" it.
Well, of course the actual application is in the JAR file, and the
only PowerPC thing I could find is the little launcher executable
in the App->Contents->MacOS directory. So, I tried setting the
project's architecture to i386+ppc, but it has no effect on the
little executable, even when I clean or otherwise delete the thing.
This is not a big deal, since our app is not actually running
under Rosetta at all, being a Java app, but can anyone tell me
just how to build that little executable as a UBin?
Paul
We have now sunk to a depth at which the restatement of the
obvious is the first duty of intelligent men.
George Orwell
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