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Re: Any way to get a warning if a non-boolean type is used in an if expression?
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Re: Any way to get a warning if a non-boolean type is used in an if expression?


  • Subject: Re: Any way to get a warning if a non-boolean type is used in an if expression?
  • From: Jens Alfke <email@hidden>
  • Date: Fri, 18 Oct 2013 11:44:26 -0700


On Oct 18, 2013, at 11:07 AM, Quincey Morris <email@hidden> wrote:

Um, one of these things is not like the other.

OK, then basically it was a think-o where he forgot that it needed the .boolValue transformation to become a real boolean. That’s slightly different from what I remembered, but the point is the same.

My point (which perhaps made more sense at 2 am when I came up with it) is that the boolean-ness of 'if (x)' isn't the issue in Rick's case. In C, 'if (x)' is *exactly* equivalent to 'if (x != 0)', which is as boolean-looking a test as Rick could wish, but would be just as wrong as the original code, if 'x' was 'self.active’.

But you wouldn’t write “if (x != 0)” for a case where x is (or you believe it to be) a boolean. You’d just write “if (x)”. That’s where the warning would help, by flagging that line if x were not, in fact, a boolean. This would have helped Rick find his mistake at compile time.

—Jens
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References: 
 >Re: Any way to get a warning if a non-boolean type is used in an if expression? (From: Quincey Morris <email@hidden>)
 >Re: Any way to get a warning if a non-boolean type is used in an if expression? (From: Jens Alfke <email@hidden>)
 >Re: Any way to get a warning if a non-boolean type is used in an if expression? (From: Quincey Morris <email@hidden>)

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