Re: slicing in Swift
Re: slicing in Swift
- Subject: Re: slicing in Swift
- From: Jonathan Hull <email@hidden>
- Date: Tue, 06 Sep 2016 17:55:14 -0700
I realized my comment may not have been clear. Here is the actual code (written in Mail):
var numbers: [UInt64] = …
func numbers( upTo nbr: Int ) -> [UInt64]
{
return Array( numbers[ 0 ..< nbr ] )
}
Thanks,
Jon
> On Sep 6, 2016, at 5:42 PM, Jonathan Hull <email@hidden> wrote:
>
> You can explicitly create an array with the slice by using ‘Array(slice)’. Honestly, I am not sure of the actual value of slices because of issues like this. I would rather have those methods return an Array which is some sort of copy on write slice internally.
>
> Thanks,
> Jon
>
>> On Sep 6, 2016, at 5:33 PM, Gerriet M. Denkmann <email@hidden> wrote:
>>
>> var numbers: [UInt64] = …
>>
>> func numbers( upTo nbr: Int ) -> [UInt64]
>> {
>> let slice = numbers[ 0 ..< nbr ]
>> return slice
>> // Cannot convert return expression of type ‘ArraySlice<UInt64>' to return type '[UInt64]'
>>
>> // workaound:
>> var outCopy:[UInt64] = []
>> for i in 0 ..< nbr { outCopy.append( numbers[i] ) }
>> return outCopy
>> }
>>
>> Any better way to do this?
>>
>> Gerriet.
>>
>>
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