Deserializing Exception [Web Services Newbie]
Deserializing Exception [Web Services Newbie]
- Subject: Deserializing Exception [Web Services Newbie]
- From: Ian Baxter <email@hidden>
- Date: Fri, 23 Jan 2004 14:17:53 -0600
Hi,
I'm setting up my first web services client and I'm getting an
exception (see bottom of email) when I invoke the web service. I'm very
new to web services, so I'm sure I'm just missing something simple...
I used WSDL2Java to setup my objects and used the AmazonClient example
to setup the rest. I'm also certain that all of the serializers and
deserializers have been registered for my classes. Any help would be
much appreciated.
Thanks,
Ian
org.xml.sax.SAXException: Deserializing parameter 'PlaceOrderResult':
could not find deserializer for type {java}org.w3c.dom.Element
at org.apache.axis.message.RPCHandler.onStartChild(RPCHandler.java:276)
at
org.apache.axis.encoding.DeserializationContextImpl.startElement(Deseria
lizationContextImpl.java:893)
at
org.apache.axis.message.SAX2EventRecorder.replay(SAX2EventRecorder.java:
200)
at
org.apache.axis.message.MessageElement.publishToHandler(MessageElement.j
ava:684)
at org.apache.axis.message.RPCElement.deserialize(RPCElement.java:241)
at org.apache.axis.message.RPCElement.getParams(RPCElement.java:265)
at org.apache.axis.client.Call.invoke(Call.java:1871)
at org.apache.axis.client.Call.invoke(Call.java:1777)
at org.apache.axis.client.Call.invoke(Call.java:1315)
at
com.webobjects.webservices.client.WOWebServiceClient.invoke(WOWebService
Client.java:486)
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